Find the value of x,if 9^x=3^x-3 exponents
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9=(3)^2
9^x = (3)^2x
(3)^2x = (3)^x-3
as bases being same , 2x = x-3
2x-x = -3
x= -3
9^x = (3)^2x
(3)^2x = (3)^x-3
as bases being same , 2x = x-3
2x-x = -3
x= -3
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