Question

Find the value of x if:

a rectangle’s length is (x+4) cm, its breadth is (x+2) cm, and its perimeter is 20 cm.

x=

Answer 1

Perimeter of a rectangle is 2(l+b)

2(x+4)+(x+2)

2*2x+6=20

4x+12=20

4x=20-12

X=6/4

=3/2

Step-by-step explanation:

Answer 2

Given :

• A rectangle’s length is (x + 4) cm.

• Breadth of the rectangle is (x + 2) cm.

• Perimeter of the rectangle is 20 cm.

To find :

• The value of x =?

Step-by-step explanation :

Perimeter of the rectangle = 20 cm. [Given]

As We know that :

Perimeter of the rectangle = 2(length + breadth)

Substituting the values in the above formula, we get,

➮ 20 = 2( x + 4 + x + 2)

➮ 20 = 2( 2x + 6)

➮ 20 = 4x + 12

Or, 4x + 12 = 20

➮ 4x = 20 - 12

➮ 4x = 8

➮ x = 8/4

➮ x = 2.

Therefore, We get the value of, x = 2 cm.

Hence,

Length of rectangle, (x + 4) = 2 + 4 = 6 cm.

Breadth of rectangle, (x + 2) = 2 + 2 = 4 cm.

Verification :

Perimeter of the rectangle = 20 cm. [Given]

Length of the rectangle = x + 4 cm.

Breadth of the rectangle = x + 2 cm

As We know that,

Perimeter of the rectangle = 2(length + breadth)

Substituting the value of x = 2 in the above formula, we get,

➮ 20 = 2( x + 4 + x + 2)

➮ 20 = 2(2 + 4 + 2 + 2)

➮ 20 = 2 (10)

➮ 20 = 20

LHS = RHS.

Hence, it is verified.