Question

find the value of x if AB||CD​

Answer 1

Answer:

hii mate here is your answer

Step-by-step explanation:

Given

The lines AB & CD are parallel to each other.

AE and CE meet at E.

Angle OAB=108°

Angle OCD=112°.

To find out

Angle AEC=?

SOLUTION

the line EF is drawn such that

EF II AB

I.e EF II CD therefore AB II CD.

Now the sum of the same side internal angles=180

therefore Angle AEF-Angle EAB

=180°-108°

=72° &

Angle CEF=180°

=180°-112°

=68°

Therefore Angle AEC=x= Angle AEF+Angle CEF

=72°+68°=140°

HOPE ITS HELP U

Answer 2

Given :-

• ∠BAO = 130°
• ∠DCO = 120°
• AB || CD

To Find :-

• value of x ?

Solution :-

construction : Draw a line PQ || AB

here, AB || PQ then,

∠BAO + ∠QOA = 180° (adjacent angles)

$\bold{ : \implies 130 \degree + ∠QOA = 180 \degree} \\ \\ \bold{: \implies ∠QOA = 180 \degree \: - 130 \degree} \\ \\ \bold{: \implies ∠QOA = 50 \degree } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

so, ∠QOA = 50°

we have AB || PQ and AB || CD

➪ PQ || CD

then,

∠DCO + ∠QOC = 180° (adjacent angles)

$\bold{: \implies120 \degree + ∠QOC = 180 \degree } \\ \\ \bold{: \implies ∠QOC = 180 \degree - 120 \degree } \\ \\ \bold{: \implies ∠QOC = 60 \degree } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

so, ∠QOC = 60°

now, we have to find value of x

∠x = ∠QOA + ∠QOC

$\bold{: \implies ∠x = 50 \degree + 60 \degree} \\ \\ \bold{: \implies ∠x = 110 \degree } \: \: \: \: \: \: \: \: \: \:$

so, value of x is 110