Question

Find the value of x if
abx=(3a+b)^2-(3a-b)^2


Plz answer fast

Answer 1

abx = (3a + b)² - (3a - b)²

=> abx = (3a + b + 3a - b)[ 3a + b - ( 3a - b) ]²

=> abx = 6a ( 3a + b - 3a + b)

=> abx = 6a × 2b

=> abx = 12ab

=> x = (12ab)/ab

=> x = 12


HOPE IT'LL HELP YOU....:)

Answer 2

Given,

$abx = (3a + b) ^{2} - (3a - b) ^{2}$

To find,

The value of x.

Solution,

The value of x will be 12.

We can easily solve this problem by following the given steps.

According to the question,

We have the following expression:

$abx = (3a + b) ^{2} - (3a - b) ^{2}$

Now, on the right-hand side, we can use the identity: (a²-b²) = (a+b)(a-b).

In this case, we have a = (3a+b) and b = (3a-b).

abx = (3a+b+3a-b) (3a+b-3a+b)

abx = 6a(2b) [The numbers with the same variables can be added or subtracted.]

abx = 12ab

x = 12ab/ab (ab was in the multiplication on the left-hand side. So, it is in the division on the right-hand side.)

x = 12

Hence, the value of x is 12.