find the value of x, if DE ia parallel to BC in a triangle ABC of sides AD =3cm , AE=2cm, EC=7cm and BD=x
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Answer:
x=10.5 cm
Step-by-step explanation:
AD=3cm
AE=2cm
EC=7cm
DB=x cm
Now according to the BPT theorem we can write-
AD/DB=AE/EC
3/x=2/7
21=2x
x=21/2
x=10.5cm
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