Question

Find the value of x, if distance between
two points P (2, -3) and Q(x,-7) is 5​

Answer 1

Step-by-step explanation:

suppose P =(X1,Y1)

Q= (X2,Y2)

By Distance Formula

formula dalke Values put karke aapka ans aata aagayega

Answer 2

Answer:

X=11, if this is not right try to ask your teacher.

Step-by-step explanation:

Formula: √(x2-x1)²+(y2-y1)²

.°. PQ= √(x-2)²+[-7-(-3)]²

.°. 5= √(x-2)²+(-7+3)²

.°.5=√(x-2)²+(-4)²

.°. 5= x-2 - 4

.°. 5= x-6

.°. 5+6=x

.°. 11=x

.°. x=11