Find the value of x if log(x-4)+log(x+2)=log(2x-3)
Answers
Answered by
0
Step-by-step explanation:
log(x-4)+log(x+2)=log(2x-3)
log(x-4) (x+2) = log (2x-3)
x^2-2x-8 = 2x-3
x^2-4x-5 =0
x^-5x+ x-5 = 0
x(x-5) +1 (x-5) =0
(x-5)(x+1) =0
x= 5 or -1
Similar questions