Question

Find the value of x, if log(x+5) + log(x-5) = 4log2 + 2log3​

Answer 1

Step-by-step explanation:

We have,

$\log(x + 5) + \log(x - 5) = 4 \log(2) + 2 \log(3)$

$\implies \log({x}^{2} - 25) = \log({2}^{4}) + \log({3}^{2})$

$\implies \log({x}^{2} - 25) = \log(16 \times 9)$

$\implies {x}^{2} - 25 = 144$

$\implies {x}^{2} = 169$

$\implies x= ± 13$