find the value of x if logx base 8 equal to 2.5 and logy base 2 equal to 6
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Answer:
log (base 2)x+log (base 2)y>=6
=> log (base 2)xy >=6
[Express 6 as log (base 2) ; 6=log(base 2)2^6.]
Now log (base 2)xy > =log (base 2)2^6
Or log (base 2)xy > = log (base 2)64
Or xy > = 64
Or x= >64/y or x=64/y □ ANSWER.
[ HERE y is Positive Real Number & Not equal to ZERO ]
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