Math, asked by sharvaric7, 6 months ago

find the value of x ,if m=1-3x/2,n=1-2 x/3 and 3(n_2m)-1=0​

Answers

Answered by adityarawat28122004
1

Answer:

x= -3 answer

Step-by-step explanation:

m = (1-3x)/2 and, n (1-2x) /3

= 3(n-2m)-1=0 (replace the values)

= 3{(1-3x/2)-2(1-2x/3)}-1=0

= 3{1-3x/2-(2-4x/3)}-1= 0

= 3(3-9x-4+8x/6)-1=0

= 3(-1-x/6)-1=0

= -3-3x/6 -1=0

= -3-3x-6/6=0

= -9-3x=0*6

= -3x=9

= x=9/-3

= x= -3 answer

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