Question

find the value of x if p+1=0 and x^2+px-6=0

solve it step by step and i will mark you brainliest

Answer 1

Answer:

x = 3 , -2

Step-by-step explanation:

since, p+1=0

Therefore p=-1

Putting the value of P in the given equation....

x²+px-6=0

x²+(-1)x-6=0

x²-x-6=0

x²-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

x-3=0 or x+2=0

x=3 or x=-2

Therefore, x=3,-2

Answer 2

p + 1 = 0

p = -1

x² + px - 6 = 0

x² - x - 6 = 0

x² - 3x + 2x - 6 = 0

x(x - 3) +2(x - 3) = 0

(x + 2) (x - 3) = 0

x + 2 = 0 or x - 3 = 0

x = -2 or x = 3 is Answer