Question

find the value of x if p+7=0 and q-12=0 and x^2+px+q=0​

Answer 1

Answer:

p+7 = 0

p = -7

q-12 = 0

q = 12

x²+px+q = 0

x²+(-7)(x)+12 = 0

x²-7x+12 = 0

x²-3x-4x+12 = 0

x(x-3)-4(x-3) = 0

(x-3)(x-4) = 0

(x-3) = 0

x = 3

(x-4) = 0

x = 4

The values of x are 3 and 4.