Math, asked by tanmay2931, 10 months ago

Find the value of x if sin 2x =sin 60°× cos 60°-cos 60°×sin 30°​

Answers

Answered by Anonymous
1

 \sin(2x)  =  \sin(60)  \times  \cos(60)  -  \cos(60)  \times  \sin(60)  \\  \sin(2x)  =  \frac{ \sqrt{3} }{2}  \times  \frac{1}{2}  -  \frac{1}{2}  \times  \frac{ \sqrt{3} }{2}  \\  \sin(2x)  =  \frac{ \sqrt{3} }{4}  -  \frac{ \sqrt{3} }{4}  \\  \sin(2x)  = 0 \\ 2x = 0 \\ x = 0

hope it helps you

Similar questions
Math, 10 months ago