Question

find the value of x if
$3 ^{2x - 1} \div 9 = 27$
(no stupid answers plzz)​

Answer 1

Answer:

Hii mate..

your solution

Answer 2

Answer:

The value of x is 3

Step-by-step explanation:

$Q. = > \: \: 3 {}^{2x - 1} \div 9 = 27$

we can write it as ,

$\frac{3 {}^{2x - 1} }{9} = 27 \\ \\ = > \frac{3 {}^{2x - 1} }{ {3}^{2} } = 27 \\ \\ = > {3}^{2x - 1 - (2)} = 27 \: \: \: \: \: \: \: \: \: \: \: \: \: \: ( \frac{x {}^{2} }{x} =x {}^{2 - 1} ) \\ \\ = > 3 {}^{2x - 3} = {3}^{3} \\ \\ bases \: are \: same \: \: so \: we \: equate \: \\ powers \\ \\ = > 2x - 3 = 3 \\ \\ = > 2x = 3 + 3 \\ \\ = > 2x = 6 \\ \\ = > x = \frac{6}{2} \\ \\ = > x = 3$

thus, the value of x is 3.

Please Mark As BRAINLIEST ..