Question

find the value of x if
$3 {}^{x} \times 3 ^{x2} = 3 {}^{ - 6}$
​

Answer 1

${3}^{x} \times {3}^{2x} = {3}^{ - 6} \\ {3}^{x + 2x} = {3}^{ - 6} \\ {3}^{3x} = {3}^{ - 6} \\ { \tt{on \: comparing \: exponentially}} \\ 3x = - 6 \\ x = \frac{ - 6}{2} \\ \\ x = - 3$

║VanditaNegi║