Math, asked by wolfi, 1 month ago

find the value of x if -
 {5 }^{2x + 1} \div 25 = 125

Answers

Answered by suraj5070
201

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

\sf \bf {5}^{2x + 1} \div 25 = 125

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

\sf \bf\implies {5}^{2x + 1} \div 25 = 125

\sf \bf\implies {5}^{2x + 1} \div {5}^{2} = {5}^{3}

\sf \bf\implies {5}^{2x + 1-2}= {5}^{3}

 \tt {\underbrace {Now\: equate\: only\: the\: powers}}

 \sf \bf \implies 2x+1-2=3

 \sf \bf \implies 2x-1=3

 \sf \bf \implies 2x=3+1

 \sf \bf \implies 2x=4

 \sf \bf \implies x=\dfrac{4}{2}

 \implies{\boxed {\color {green} {\sf \bf x=2}}}

 \sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}

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 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 \tt \underline{Identities}

 \sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}

 \sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}

 \sf \bf (a+b) (a-b) ={a}^{2}-{b}^{2}

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