Question

find the value of x if $\sqrt{1369}$ + $\sqrt{0.0615 + x}$ = 37.5

Answer 1

Answer:

${ {2 \frac{5 { { { {4 {y \frac{5 \frac{1. \sqrt[ < mmceaty]{?} \times \frac{?}{?} }{?} }{?} }^{?} }^{2} }^{?} q}^{2} }^rysfy {6 \frac{1 {5 {1 \frac{y {x65 \frac{ \frac{2 \sqrt{ \sqrt{?} } }{?} }{?} \times \frac{?}{?} }^{2} }{?} }^{2} }^{2} }{?} }^{2} {?}fadys }{?} }^{2} }^{?}$

Answer 2

Answer:

−3

1369

+

0.0615+x

=37.25

⇒

0.0615+x

=37.25−

1369

=37.25−37=0.25

⇒0.0615+x=(0.25)

2

=0.0625

⇒x=0.0625−0.0615=0.001=

10

3

1

=10

−3