Question

Find the value of x if

$\sqrt{ {( \frac{3}{5} )}^{1 - 2x} } = 4 \frac{17}{27}.$

Answer 1

◆ SOLUTION ◆

$<b><i> squaring both side we get$

$= ( { \frac{3}{5} })^{1 - 2x} = ({ \frac{125}{27} })^{2}$

$\implies \: ( { \frac{3}{5} })^{1 - 2x} = (({ \frac{5}{3} })^{ {3 })^2} =( { \frac{5}{3} )}^{6}$

$\implies \: ({ \frac{3}{5} )}^{1 - 2x} = ( { \frac{3}{5} )}^{ - 6} \implies \: 1 - 2x = - 6$

$\implies \: 2x = 7$

∴ $x = \frac{7}{2} = 3 \frac{1}{2}$

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Answer 2

Answer:

hola mate.

see the attachment

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