FIND THE VALUE OF X IF THE ARITHMETIC MEAN OF XSQUARE , 6X ,2 IS 6
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1
Answer:
2
Step-by-step explanation:
given that,
6 = (x^2+6x+2)/3
18 = x^2 + 6x + 2
18-2 = 16 = x^2 + 6x
let x = 1
16 = 1^2 + 6(1)
16 is not equals to 1 + 6
so,
let x= 2
16 = 2^2 + 6(2)
16 = 4 + 12 = 16
so x = 2
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*sudipto*
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