find the value of x if the distance between (a) (9,-5)(b)(12,x) is three
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Distance = 3
So distance^2 = 3^2
(12-9)^2 + (x-(-5))^2 = 9
3^2 + (x+5)^2 = 9
(x+5)^2=0
x^2 + 25 +10x = 0
x^2 + 10x + 25 = 0
x^2 + 5x + 5x +25=0
x(x+5) + 5(x+5)=0
(x+5)(x+5)=0
O the value of x is -5
So distance^2 = 3^2
(12-9)^2 + (x-(-5))^2 = 9
3^2 + (x+5)^2 = 9
(x+5)^2=0
x^2 + 25 +10x = 0
x^2 + 10x + 25 = 0
x^2 + 5x + 5x +25=0
x(x+5) + 5(x+5)=0
(x+5)(x+5)=0
O the value of x is -5
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