Question

Find the value of x, if the distance between the points A(0,0) and B(x, -4) is 5 units​

Answer 1

Step-by-step explanation:

AB =

$\sqrt{(x2 - x1) { }^{2} +(y2 - y1) {}^{2} {} }$

5 =

$\sqrt{(0 - x) {}^{2} + (0 + 4) {}^{2} }$

5 =

$\sqrt{( - x) {}^{2} + (4) {}^{2} }$

5=

$\sqrt{x {}^{2} + 16 }$

$5 {}^{2} = x {}^{2} + 16$

$25 = x {}^{2} + 16$

$25 - 16 = x {}^{2}$

therefore

$x {}^{2} = 9$

therefore

$x = \sqrt{9}$

therefore

$x = 9$