Question

Find the value of x if the points (2x,2x),(3,2x+1)and (1,0) are collinear. Solve the

Answer 1

value of x is (2 ± √2)/4

given, the points (2x, 2x) , (3, 2x + 1) and (1, 0) are colinear. we have to find value of x.

we know, three points are colinear only if

we know, three points are colinear only if area of triangle = 0

⇒1/2 [2x(2x + 1 - 0) + 3(0 - 2x) + 1(2x - 2x - 1)] = 0

⇒1/2 [2x(2x + 1) - 6x - 1] = 0

⇒1/2 [4x² + 2x - 6x - 1 ] = 0

⇒4x² - 4x - 1 = 0

⇒x = {4 ± √(4² - 2 × (-4) × (-1)}/2(4)

= {4 ± √(16 - 8)}/8

= (4 ± 2√2)/8

= (2 ± √2)/4

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Answer 2

Answer:

Thanx for 13 points......