Question

Find the value of 'x' if the terms 3x-1, 15, 3x+1 are in AP ​

Answer 1

The value of x = 5

Given :

The terms 3x - 1 , 15 , 3x + 1 are in AP

To find :

The value of x

Concept :

If a , b , c are three consecutive terms of an AP then a + c = 2b

Solution :

Step 1 of 2 :

Form the equation

Here it is given that 3x - 1 , 15 , 3x + 1 are in AP

We know that if a , b , c are three consecutive terms of an AP then a + c = 2b

By the given condition

( 3x - 1 ) + ( 3x + 1 ) = 2 × 15

Step 2 of 2 :

Find the value of x

( 3x - 1 ) + ( 3x + 1 ) = 2 × 15

⇒ 3x - 1 + 3x + 1 = 30

⇒ 6x = 30

⇒ x = 30/6

⇒ x = 5

Hence the required solution is x = 5

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Answer 2

Answer:

The required solution is 5.

Step-by-step explanation:

As per the data given in the question we have to find the value of x

As per the question it is given that the terms 3x-1, 15, 3x+1 are in AP ​

Here it is given that 3x - 1 , 15 , 3x + 1 are in AP

Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

Difference between consecutive terms is not same. so this is not an A.P.

We know that if a , b , c are three consecutive terms of an AP then

a + c = 2b

By the given condition

( 3x - 1 ) + ( 3x + 1 ) = 2 × 15

then,

⇒ 3x - 1 + 3x + 1 = 30

⇒ 6x = 30

⇒ x = 30/6

⇒ x = 5

Therefore, if the term 3x-1, 15, 3x+1 are in AP ​then value of x=5

Hence the required solution is 5

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