Find the value of ‘X’ if vector a is perpendicular to vector b, if a=2i-j+k and b=3i+2j-xk.
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given
Ā=2i-j+k
B=3i+2j-xk
let c be the angle between them (I. e π/2)
we know that
cos c =lA. Bl / lAl lBl. eq1
lA. Bl=2(3)+(-1)(2)+1(-x)
=4-x
lAl=√2^2+1^2+1^2
=√6
lBl=√3^2+2^2+x^2
=√13+x^2
cos π/2=0
from eq 1
lA. Bl=0
4-x=0
x=4
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