find the value of x if x-(1/x)=51
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x - 1/x = 51
x² - 51x - 1 = 0
x = {51 +√(51² +4*1)}/2 or {51 - √(51² +4*1)}
x = (51+51.04)/2 or (51 - 51.04)/2
x = 51.02 or -0.02
x² - 51x - 1 = 0
x = {51 +√(51² +4*1)}/2 or {51 - √(51² +4*1)}
x = (51+51.04)/2 or (51 - 51.04)/2
x = 51.02 or -0.02
brohini23800rohi:
thanks Vikaskumar0507 but i dont know the formulae you used i have not reached the level
if ax^2 + bx + c = 0 is quadratic equation then x = {-b +or- (b^2-4ac)^1/2}/2a
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Answer:
Step-by-step explanation:
Ggk 51
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