Question

find the value of x if x^2+12=28 value of x​

Answer 1

Answer:

$\rm x= 4$

Step-by-step explanation:

We have,

$\rm x^2+12=28$

$\rm x^2=28-12$

$\rm x^2=16$

$\rm x= \sqrt{16}$

$\rm x= 4$

Answer 2

Given: The equation is$x^2+12=28$.

We have to find the value of$x$.

• By using the concept of equation shifting, we are solving the above equation.  
• For this, we will separate the variables on one side and the constant o another side.  
• Then, we will simplify the equation.  

We are solving in the following way:  

We have,

$x^2+12=28$

$=>x^2=28-12\\=>x^2=16\\=>x=\sqrt{16} \\=>x=\sqrt{4\times4} \\=>x=+4\ or\ -4$

Hence, the value of$x$ is$+4\ or\ -4$.