Find the value of x, if
X-2 2x-3 3x - 4
X-4 2x-9 3x - 16 = 0
X-8 2x -27 3x - 64
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3
Given, expanding along R1 we get =>(x - 2) (84 - 72) - 1 (84 - 36) + 2 (24 - 12) = 0 =>12x - 24 - 48 + 24 = 0 =>12x = 48 => x = 4Read more on Sarthaks.com - https://www.sarthaks.com/57509/using-properties-of-determinants-solve-the-following-for-2-2x-3-3x-4-x-4-2x-9-3x-16-x-8-2x-27-3x-64
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1
Answer:
x - 4 is factor of
x−2 x−4 x−8
2x−3 2x−9 2x−27
3x−4 3x−16 3x−64
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