Find the value of x if x, (2x + 13°), (3x + 10º) and (x – 6°) are all the angles of a quadrilateral ?
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Step-by-step explanation:
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Step-by-step explanation:
X + (2x + 13°) +(3x+ 10°) + (x-6°) = 360°
X + 2x + 13° + 3x + 10° + X - 6° = 360°
7x + 17° = 360°
7x = 360° - 17°
7x = 343°
X = 343°/7
X = 49°
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