Find the value of x, if x-xtan²30/1+tan²30 = sin²30+4cot²45-sec²60
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the value of x is 60 please mark me as brainlist
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sin30 = 1/2
cot45 = 1
sec60 = 2
cosec45 = √2
sec30 = 2/√3
⇒ (sin²30°+ 4cot²45° - sec²60) (Cosec²45° sec²30°)
⇒ [ (1/2)² + 4(1)² - 2² ] [ (√2)² * (2/√3)² ]
⇒ [ 1/4 + 4 - 4 ] [ 2 * 4/3 ]
⇒ [ 1/4 ] [ 8/3 ]
⇒ 2/3
Therefore, (sin²30°+ 4cot²45° - sec²60°) (Cosec²45°sec²30°) = 2/3
Answer by @Krishhhhnna
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