Question

find the value of x in 2 sin3x =/3

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Answer 1

$➛ \sin(3x) = \sqrt{ \frac{3}{2} }$

$➛ \sf \: since \: \sin60 {}^{0} = \sqrt{ \frac{3}{2} }$

$\sf \: therefore \\ \sf \: \sin3x = \sqrt{ \frac{3}{2} }$

$\sf \: sin3x = sin60 {}^{0} \\ \sf \: 3x = 60 {}^{0} \\ \sf \: x = \frac{ 60{}^{0} }{3} \\ \sf \: x = 20 {}^{0}$