Math, asked by amaansheikh7339, 11 months ago

Find the value of x in 3+2^x=〖(64)〗^(1/2)+〖(27)〗^(1/3)

Answers

Answered by saidhumal29

1

Answer:

3 + 2x = (64)1/2 + (27 )1/33 + 2x = 64/2 + 27/33 + 2x = 32 + 93 + 2x = 41 2x = 41 - 32x = 38 x = 38/2x = 19hope it ...

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