Question

find the value of x in (3/4)^x-1=9/16

Answer 1

GIVEN :

Find the value of x in $(\frac{3}{4})^{x-1}=\frac{9}{16}$

TO FIND :

The value of x from the given equation

SOLUTION :

Given equation is $(\frac{3}{4})^{x-1}=\frac{9}{16}$

$(\frac{3}{4})^{x-1}=\frac{3^2}{4^2}$

By using the property of exponents :

$\frac{a^m}{b^m}=(\frac{a}{b})^m$

$(\frac{3}{4})^{x-1}=(\frac{3}{4})^2$

Since in the above equation their bases are equal we can equate their powers,

x-1 = 2

x = 2+1

⇒ x = 3

∴ the value of x in the given equation is 3

Answer 2

Answer:

(3/4)^1

(3/4^2)

x-1=2

x=2+1

x=3

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