Question

Find the value of x in 31k2 if x is divisiable by 6

Answer 1

Answer:

3+1+k+2= 6

6+k=6

k=6-6

k = 1

Answer 2

Answer:

The value of x might be 3, 6 or 9

Step-by-step explanation:

the divisibility rule for 2 is the last digit should be even number

so the last digit is 2..and it is even number...so it is divisible by 2

the divisibility rule for 3 is sum of all digits should be divisible by 3

so by trail and error method

3+1+1+2=7 [not divisible]

3+1+2+2=8 [not divisible]

3+1+3+2=9    [divisible]

3+1+4+2=10[not divisible]

3+1+5+2=11[not divisible]

3+1+6+2=12   [divisible]

3+1+7+2=13[not divisible]

3+1+8+2=14[not divisible]

3+1+9+2=15    [divisible]

so the value of x may be 3 or 6 or 9