Find the value of X in 9^x= 27^2
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9^x = 27^2
(3^2)^x = (3^3)^2
Now,
(a^m)^n = a^m*n
So
3^2*x = 3^3*2
3^2x = 3^6
As the bases are equal thus the powers will also be equal.
2x = 6
Therefore
x = 6/2
x = 3.
Hope this helps....
(3^2)^x = (3^3)^2
Now,
(a^m)^n = a^m*n
So
3^2*x = 3^3*2
3^2x = 3^6
As the bases are equal thus the powers will also be equal.
2x = 6
Therefore
x = 6/2
x = 3.
Hope this helps....
Indu9156:
I liked your answer
Answered by
1
9^x = 27^2
=> 9^x = 3^2×3
=> 3^2x = 3^2×3
therefore, x = 3
hope ot helps
=> 9^x = 3^2×3
=> 3^2x = 3^2×3
therefore, x = 3
hope ot helps
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