Question

Find the value of x in a isosceles trapezoid

Answer 1

Answer:

• It is given that two diagonals of isosceles trapezium are x cm. and (3x-8)cm.

• According to Isosceles Trapezoid Diagonals theorem, the diagonals of isosceles trapezium are congruent.

3x-8=x3x−8=x

Add 8 on both sides.

3x-8+8=x+83x−8+8=x+8

3x=x+83x=x+8

Subtract x from both sides.

3x-x=x+8-x3x−x=x+8−x

2x=82x=8

Divide both sides by 2.

x=\frac{8}{2}x=

2

8

x=4x=4

• Therefore, the value of x is 4 cm.