find
the value
of x
in each
Case
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Answer:
x=80°
Step-by-step explanation:
In triangle ABC,
QT and PS intersect at point O.
In triangle PTO,
Angle PTO=90°.....(given)
Angle TPO=30°.....(given)
Angle POT=60....(remaining angle of
triangle)
Angle QOS=Angle POT...(opposite angle)
but Angle POT=60°
Therefore,
Angle QOS=60°..... (1)
In triangle QOS,
Angle QOS=60°....(from 1)
Angle OQS=40°....(given)
Angle OSQ=80°...(remaining angle of
triangle)
x=Angle OSQ=80°
X=80°
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