Question

find the value of x in each case

Answer 1

In triangle ABC
angle A + angle B+ angle C=180°
60°+45°+ angle C= 180°
angle C = 180-105
= 75°
Now angle C = angle DCE (Vertically Opp. angles)
in triangle DCE
angle D+ angle E+ angle DCE = 180°
80°+x+75° =180°
angle x = 25°
ans

Answer 2

let in triangle abc

angle bac+angle abc+angle acb=180

(sum of measures of angkes of triangle)

60+45+angle acb=180

105+angle acb=180

Angle acb=180-105

=75

angle dce= angle acb( vertically oppoisite angle)

HEnce angle dce=75

And in triangle dce

Angle dce+angle ced+angle cde=180

75+80+x=180

155+x=180

X=180-155

X=25