Question

Find the value of X in each case:
(7)^6÷(7)^4-x=(7)^8

Answer 1

by the law of exponent

(7)^ 6 -(4 -x) = 7^8

7^6 -4 + x = 7^8

7 ^ 2 +x = 7^8

comparing both sides having same base

2+x = 8

x= 8 -2

x = 6