Question

Find the value of x in each case. Give reasons to justify your solutions!

Answer 1

Answer:

DBC= 65 degree because ADB AND bdc are liner pair so 180-50= 130

2x= 130( because sum of the triangle is. 180)

130/2= 65

and second one I can't find out

Answer 2

The value of x is 25.

Step-by-step explanation:

Given information: AE║BC, $\angle ADB=50^{\circ}$.

According to angle sum property, the sum of interior angles of a triangle is 180 degree.

In triangle ABD,

$\angle DAB+\angle DBA+\angle ADB=180$

$\angle DAB+\angle DBA+50=180$

$\angle DAB+\angle DBA=180-50$

$\angle DAB+\angle DBA=130$             .... (1)

If a transversal line intersect two parallel lines then same sided interior angles are supplementary angles.

AE║BC, it means ∠EAB and ∠CBA are supplementary angles.

$\angle EAB+\angle CBA=180$

$(x+\angle DAB)+(x+\angle DBA)=180$

$2x+(\angle DAB+\angle DBA)=180$

Using (1) we get

$2x+130=180$

$2x=180-130$

$2x=50$

$x=25$

Therefore, the value of x is 25.

#Learn more

Find the unknown angles marked in each of the following figures.

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