Find the value of x in each case. Give reasons to justify your solutions!
H∈ IG
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Given, <JHI = 156°
we have know that,
<JHI + <JHG = 180°
=> 156° + <JHG = 180°
=> <JHG = 24°
_ _
Here, HG and EG are parallel to each other and HG is the intersection between them .
So, <JHG = <FGH
=> <FGH = 24° .
we have,
<EFH + <GFH = 180°
=> 2x + <GFH = 180°
=> <GFH = (180° - 2x)
Also, In ∆HGF:-
x° + (180 - 2x)° + <FGH = 180°
=> <FGH = 180° - 180° + x°
=> <FGH = <x
=> <x = 24° .
Hence,
<JHI = 156°, <JHG = 24°, <EFH =48°,
<GHF = 24°,<HGF =24°,<GFH=132° .
Hope it helps to you.
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