Find the value of x in each case. Pls explain me.
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Answer:
POQ=∠SOT (vertically opposite angles
∴∠POQ=40
∘
)
∠OQR=∠OPQ+∠POQ (∵ exterior angle= sum of opposite interior angles)
125
∘
=x
∘
+40
∘
⇒x
∘
=125
∘
−40
∘
=85
∘
∴∠OPQ=85
∘
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