Question

Find the Value of x in each following :-

$\sf{1.) \sqrt[3]{3x - 2} = 4 } \: \\ \\ \sf {2.) \sqrt[5]{5x + 2} = 2 }$
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Answer 1

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$\huge\boxed{\bf{\red{\fcolorbox{blue}{white}{Answer}}}}$

$\sf{1.) \sqrt[3]{3x - 2} = 4 } \: \\ \sf \small{ \implies \: ( \sqrt[3]{3x - 2} )^{3} = 4 ^{3} } \\ \sf \small{ \implies \: 3x - 2 = 64 } \\ \sf \small{ \implies \: 3x = 66} \\ \sf \small \red{ \implies \: x = \frac{ \cancel{66}}{ \cancel 3} ^{22} } \\ \sf \small \red{ x = 22}$

$\sf{2.) \sqrt[5]{5x + 2} = 2 } \: \\ \sf \small{ \implies \: ( \sqrt[5]{5x + 2} )^{5} = 2 ^{5} } \\ \sf \small{ \implies \: 5x + 2 = 32 } \\ \sf \small{ \implies \: 5x = 30} \\ \sf \small \red{ \implies \: x = \frac{ \cancel{30}}{ \cancel 5}^{6} } \\\sf \small \red{ x = 6}$

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