find the value of x in each of the following
Attachments:
Answers
Answered by
2
Step-by-step explanation:
i) 5x+2=2^5
5x+2=32
5x=32-2
5x=30
x=6
ii) 3x-2=4^3
3x-2=64
3x=66
x=22
iii) (3/4)^3= 3^3/4^3
(4/3)^-7=(3/4)^7=3^7/4^7
(3/4)^3(4/3)^-7=(3/4)^3(3/4)^7=(3/4)^10
(3/4)^(2×5)=(3/4)^(2x)
hence x=5
v) 3^(3x+2x-x)=3^5
3^4x=3^5
hence 4x=5
x=5/4
Similar questions