find the value of x in each of the following diagrams
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IN 1. the value of x will be 40 as
115=2x-5+x ( exterior angle is equal to the sum of opposite angle of triangle)
115=3x-5
115+5=3x
120=3x
x=120/3x
x=40
IN 2.t he value of x will be 55
as 80 + 45(alternate interior angle )+x=180
x= 55
IN 3. the value of x is 13 as
72+45+50+x=180
167+x=180
x=13
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Figure 1 - X= 2x-5+X= 115°
X=3x-5=115°
X=3x= 115+5=120°
X =120÷3 = 40
2X-5= 40×2-5=75°
X=40°
Angles are 75°, 40°,65°
Figure 2:- X= 180-(80+45)(When a line is cut by transversally)
=55°
Figure 3:-
180-(50+72+45)
=13°
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