find the value of x in fig.
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area of triangle abd =area of triangle acd.(diagonal bisect the triangle into 2 triangles of equal area.)
x2=dc2+ad2(pythagoras theorem)
so x2=42+902
x2=16+180
x2=196
x=196/2
x=98cm2.
hope it helps plz mark my answer brainlist answer
x2=dc2+ad2(pythagoras theorem)
so x2=42+902
x2=16+180
x2=196
x=196/2
x=98cm2.
hope it helps plz mark my answer brainlist answer
MAANAL:
it is wrong answer because the right answer is 8
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