Question

Find the value of x in given , for which PQ//RS .​

Answer 1

Answer:

In question ∆PTQ &∆RTS have same characters

So we tell that

RT/PT=TS/TQ

than ,RT/(RT+PR)=TS/TQ=RS/PQ than,

x-1/(x-1+x+3)=x-3/x+1

or,x-1/{2×(x+1)}=x-3/x+1

or,(X-1)=2×(X-3) because X+1 cut the value of X+1 is not equal to 0

X become 5

SO THE VALUE OF X BECOME 5