Question

find the value of x in it:

Answer 1

$\sqrt{ x + 5} + \sqrt{x} = 5 \\ = > \sqrt{x + 5} = 5 - \sqrt{x} \\ = > x + 5 = {(5 - \sqrt{x} )}^{2} \\ = > x + 5 = 25 - 10 \sqrt{x} + x \\ = > - 10 \sqrt{x} + 20 = 0 \\ = > - 10( \sqrt{x} - 2) = 0 \\ = > - \sqrt{x} + 2 = 0 \\ = > - \sqrt{x} = - 2 \\ = > \sqrt{x} = 2 \\ = > x = {2}^{2} \\ = > x = 4.$
The answer to the question is:-
D)4

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Answer 2

Answer:

hey options d is correct