Question

find the value of x in of the following​

Answer 1

2^x + 2^x + 2^x = 192

=> 3(2^x) = 192

=> 2^x = 64

=> 2^x = 2^6

=> x = 6.

Answer 2

$2 ^{x} + 2 ^{x} + 2 ^{x} = 192 \\ = before \: 2 \: taking \: as \: coeffiient \: as \: 1 + 1 + 1 = 3 \\ = 3 \times 2 ^{x} = 192 \\ = 2 {}^{x} = \frac{192}{3} \\ = 2 {}^{x} = 64 \\ = writing \: in \: exponent \\ = 2 {}^{x} = 2 ^{6} \\ = > x = 6$