Find the value of x in quadratic equation direct formula
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Answered by
2
IT'S ACQUIRED BY USING DIRECT PROFILE OF RESOLVING QUADRATICS ASLIKE IT'S VALUE IS EQUAL TO
ax² + bx + c = 0
WHERE , ALPHA AND BETA ARE THE ROOTS RESPECTIVELY
→ k [ x - α ] [ x - β ]
WHERE k = any non - zero constant
WHERE ALPHA AND BETA ARE THE ROOTS RESPECTIVELY
ax² + bx + c = 0
WHERE , ALPHA AND BETA ARE THE ROOTS RESPECTIVELY
→ k [ x - α ] [ x - β ]
WHERE k = any non - zero constant
WHERE ALPHA AND BETA ARE THE ROOTS RESPECTIVELY
Answered by
2
In quadratic equation
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the simplest way to solve,... "ax² + bx + c = 0" for the value of x is the factor of quadratic eqn and each factor has also equal to zero.
where a, b, and c are the numerical coefficients of the terms of the quadratic.
Hope this helps uh!
____________________________________________________________
the simplest way to solve,... "ax² + bx + c = 0" for the value of x is the factor of quadratic eqn and each factor has also equal to zero.
where a, b, and c are the numerical coefficients of the terms of the quadratic.
Hope this helps uh!
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