Question

find the value of x in
$\sqrt[5]{3x + 2} - 2 = 0$
The answer is x=10
Note :remember you have to explain me properly. And don't spam
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Answer 1

Answer :-

$\sqrt[5]{3x + 2} - 2 = 0 \\ = > \sqrt[5]{3x + 2} = 2 \\ = > 3x + 2 = {2}^{5} \\ = > 3x + 2 = 32 \\ = > 3x = 32 - 2 \\ = > 3x = 30 \\ = > x = 10$

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Answer 2

5

3x+2

−2=0

=>

5

3x+2

=2

=>3x+2=2

5

=>3x+2=32

=>3x=32−2

=>3x=30

=>x=10